What this page helps you practise
- number operations, fractions, decimals, and percentages
- algebra, patterns, and equations
- measurement, geometry, and spatial reasoning
- multi-step word problems and data interpretation
Year 8 Edutest mathematics assesses curriculum-based problem solving at a high level. Questions go beyond standard school exercises to test deeper understanding and application.
Try each question first, then open the worked solution to check your answer and see how to reach it.
1.A right-angled triangle has two shorter sides of 6cm and 8cm. What is the length of the longest side (hypotenuse)?
Answer: A (10 cm)
Use Pythagoras' theorem: c² = a² + b², where c is the hypotenuse. 6² + 8² = 36 + 64 = 100, and √100 = 10, so the hypotenuse is 10 cm. This is the 3-4-5 triangle doubled (6-8-10). The answer 14 adds the sides, and 100 forgets to take the square root.
2.A car's price is reduced from $20,000 to $16,000. What is the percentage decrease?
Answer: C (20%)
Percentage decrease = decrease ÷ original × 100. The decrease is $20,000 − $16,000 = $4,000. Then 4,000 ÷ 20,000 = 0.2, which is 20%. The answer 25% comes from dividing by the new price ($16,000) instead of the original. Always compare the change to the starting value.
3.If you roll a standard six-sided die twice, what is the most likely sum of the two rolls?
Answer: C (7)
There are 6 × 6 = 36 equally likely outcomes. A sum of 7 can be made in six ways (1+6, 2+5, 3+4, 4+3, 5+2, 6+1), more than any other total. A sum of 2 needs 1+1 and 12 needs 6+6, only one way each. A sum of 6 has five ways, so 7 is the most likely.
4.If a = 2 and b = -3, what is the value of a² - b?
Answer: B (7)
Substitute carefully, watching the negative sign. a² = 2² = 4. Then subtract b, which is −3: 4 − (−3). Subtracting a negative is the same as adding, so 4 + 3 = 7. The answer 1 treats it as 4 − 3, which ignores the negative sign on b.
5.Simplify: 3(x + 2y) - 2(x - y)
Answer: B (x + 8y)
Expand each bracket, taking care with the minus sign. 3(x + 2y) = 3x + 6y. −2(x − y) = −2x + 2y, because −2 × −y = +2y. Now collect like terms: 3x − 2x = x and 6y + 2y = 8y. So the answer is x + 8y. Getting +2y rather than −2y is the key step.
6.Find the median of these numbers: 5, 2, 8, 2, 9, 4, 7.
Answer: C (5)
The median is the middle value once the numbers are in order. Sorted, the list is 2, 2, 4, 5, 7, 8, 9. There are 7 numbers, so the middle one is the 4th, which is 5. A common mistake is to pick the middle of the unsorted list, which here would also be 2, so always sort first.
7.What is the probability of flipping a coin and getting heads, AND rolling a die and getting a 6?
Answer: C (1/12)
The coin and the die are independent events, so multiply their probabilities. P(heads) = 1/2 and P(rolling a 6) = 1/6. P(both) = 1/2 × 1/6 = 1/12. There are 2 × 6 = 12 equally likely combinations, and only 'heads and 6' works. Adding the probabilities instead would be wrong.
8.Find the area of a trapezium with parallel sides of 6cm and 10cm, and a height of 5cm.
Answer: B (40 cm²)
The area of a trapezium is the average of the parallel sides multiplied by the height: ½ × (a + b) × h. Here that is ½ × (6 + 10) × 5 = ½ × 16 × 5 = 8 × 5 = 40 cm². The answer 80 cm² forgets to halve, which gives the area of a rectangle twice as large.
9.A map scale is 1:50000. A road on the map is 4cm long. How long is the actual road in km?
Answer: B (2 km)
A scale of 1:50 000 means 1 cm on the map is 50 000 cm in real life. So 4 cm represents 4 × 50 000 = 200 000 cm. Convert to kilometres: 200 000 cm ÷ 100 = 2000 m, and 2000 m ÷ 1000 = 2 km. Most errors come from the unit conversion, so convert one step at a time.
10.Solve the simultaneous equations: x + y = 10 and x - y = 4.
Answer: A (x=7, y=3)
Add the two equations to eliminate y: (x + y) + (x − y) = 10 + 4, so 2x = 14 and x = 7. Substitute into x + y = 10: 7 + y = 10, so y = 3. Check in the second equation: 7 − 3 = 4. Option B also adds to 10, but its difference is only 2.
Review curriculum topics then practise with exam-style mixed question sets.
Focus on showing working and explaining methods before calculating.
Build confidence with multi-step problems where the approach is not obvious.
It covers number and algebra, measurement and geometry, statistics and probability, and multi-step problem solving at an above-curriculum level.
Edutest maths questions are typically harder and require flexible thinking rather than just applying taught procedures.