NAPLANYear 9Numeracy

NAPLAN Year 9 Numeracy Practice Test PDF

Year 9 NAPLAN numeracy requires confident reasoning across algebra, measurement, geometry, and statistics. Strong practice helps students move from recognising topics to solving unfamiliar problems efficiently.

What this page helps you practise

  • linear relationships, algebraic substitution, and equations
  • percentage change, rates, ratios, and proportional reasoning
  • surface area, volume, Pythagoras-style reasoning, and angles
  • scatterplots, data summaries, chance, and probability

Year 9 Numeracy sample questions with worked solutions

Try each question first, then open the worked solution to check your answer and see how to reach it.

  1. 1.If a car travels at 60km/h, how far does it travel in 2.5 hours?

    • A120km
    • B150km
    • C180km
    • D200km
    Show answer and working

    Answer: B (150km)

    Use distance = speed × time. The car travels 60 km every hour, so in 2.5 hours it travels 60 × 2.5. Split the time: 60 × 2 = 120 km, plus 60 × 0.5 = 30 km, giving 150 km. The answer 120 km ignores the extra half hour, so always include every part of the time given.

  2. 2.Expand: 3(x + 4)

    • A3x + 4
    • B3x + 7
    • C3x + 12
    • Dx + 12
    Show answer and working

    Answer: C (3x + 12)

    Expanding means multiplying the number outside the brackets by every term inside. 3 × x = 3x and 3 × 4 = 12, so 3(x + 4) = 3x + 12. The answer 3x + 4 only multiplies the first term, which is the most common error. Check by substituting x = 1: 3(1 + 4) = 15 and 3(1) + 12 = 15.

  3. 3.Find the hypotenuse of a right-angled triangle with sides 3cm and 4cm.

    • A5cm
    • B6cm
    • C7cm
    • D8cm
    Show answer and working

    Answer: A (5cm)

    Use Pythagoras' theorem: the square of the hypotenuse equals the sum of the squares of the other two sides. 3² + 4² = 9 + 16 = 25, and the square root of 25 is 5, so the hypotenuse is 5 cm. This 3-4-5 triangle is worth memorising. Adding 3 + 4 = 7 cm skips the squaring step.

  4. 4.What is the gradient of the line y = 2x + 3?

    • A2
    • B3
    • Cx
    • Dy
    Show answer and working

    Answer: A (2)

    A straight line written as y = mx + c has gradient m and y-intercept c. In y = 2x + 3, the number multiplying x is 2, so the gradient is 2. That means y increases by 2 every time x increases by 1. The 3 is the y-intercept, where the line crosses the y-axis, not the gradient.

  5. 5.Factorise: x² + 5x + 6

    • A(x+2)(x+3)
    • B(x+1)(x+6)
    • C(x-2)(x-3)
    • D(x+5)(x+1)
    Show answer and working

    Answer: A ((x+2)(x+3))

    To factorise x² + 5x + 6, find two numbers that multiply to give 6 and add to give 5. The pair 2 and 3 works: 2 × 3 = 6 and 2 + 3 = 5. So x² + 5x + 6 = (x + 2)(x + 3). Check by expanding: x² + 3x + 2x + 6 = x² + 5x + 6.

  6. 6.Calculate the simple interest on $1000 at 5% p.a. for 3 years.

    • A$50
    • B$100
    • C$150
    • D$200
    Show answer and working

    Answer: C ($150)

    Simple interest = principal × rate × time. Here that is $1000 × 0.05 × 3. One year of interest is 5% of $1000 = $50, and three years is 3 × $50 = $150. The answer $50 is only one year. Simple interest is calculated on the original amount each year, unlike compound interest, which grows on the new total.

  7. 7.Solve for x: 3(x − 2) = 2x + 5

    • A1
    • B7
    • C11
    • D−1
    Show answer and working

    Answer: C (11)

    Expand the brackets first: 3(x − 2) = 3x − 6, so the equation becomes 3x − 6 = 2x + 5. Subtract 2x from both sides: x − 6 = 5. Add 6 to both sides: x = 11. Check by substituting: 3(11 − 2) = 27 and 2(11) + 5 = 27, so both sides match.

  8. 8.The price of a phone increased from $400 to $460. What was the percentage increase?

    • A6%
    • B13%
    • C15%
    • D60%
    Show answer and working

    Answer: C (15%)

    Percentage increase = increase ÷ original amount × 100. The increase is $460 − $400 = $60. Divide by the original price: 60 ÷ 400 = 0.15, which is 15%. The answer 13% comes from dividing by the new price ($460) instead of the original. Always divide by the starting value when finding a percentage change.

  9. 9.What is the volume of a cylinder with radius 3 cm and height 10 cm? (Use π ≈ 3.14)

    • A94.2 cm³
    • B188.4 cm³
    • C282.6 cm³
    • D942 cm³
    Show answer and working

    Answer: C (282.6 cm³)

    The volume of a cylinder is πr²h: the area of the circular base multiplied by the height. The base area is 3.14 × 3² = 3.14 × 9 = 28.26 cm². Multiply by the height: 28.26 × 10 = 282.6 cm³. The answer 94.2 forgets to square the radius, and 188.4 is the curved surface area (2πrh).

  10. 10.A bag holds 4 red, 5 blue and 3 green marbles. One marble is chosen at random. What is the probability that it is not blue?

    • A5/12
    • B7/12
    • C1/3
    • D3/4
    Show answer and working

    Answer: B (7/12)

    There are 4 + 5 + 3 = 12 marbles in total. 'Not blue' means red or green, which is 4 + 3 = 7 marbles. So the probability is 7/12. You can also use the complement: P(blue) = 5/12, so P(not blue) = 1 − 5/12 = 7/12. The answer 5/12 is the chance of picking blue.

Preparation strategy

1

Practise multi-step problems where the first operation is not obvious.

2

Review data and graph questions separately from calculation-heavy questions.

3

Ask students to justify why an answer is reasonable.

Frequently asked questions

What topics are important for Year 9 NAPLAN numeracy?

Important topics include algebra, rates and ratios, measurement, geometry, statistics, probability, and multi-step problem solving.

How close should practice tests be to NAPLAN style?

Practice should use similar wording, mixed topics, and realistic difficulty so students build transfer skills for unfamiliar questions.

Related NAPLAN practice pages